Friday puzzle, no.22 (making up for yesterday edition)

For the first time in over 2 months, there was no post on arbitrary constant yesterday. Thus the title of today’s Friday Puzzle.

First, the answer to last week’s puzzle:

I’ve been quite poorly lately and the doctor has prescribed me a two courses of tablets (Anvilite and Bigoxy) to solve my problem and I must take one of each at the same time, once every day. These tablets are rather expensive so I’ve been very careful with them. Last night I’d just got my Anvilite tablet. I was about to get my Bigoxy tablet when two tablets fell out of the bottle into my hand and joined the Anvilite tablet. This was a major problem for me as all three tablets were identical, the same size, the same weight, and neither had any markings on it. I had to take one of each but I couldn’t tell them apart, and they were far too expensive to throw these three tablets away and start again. What did I do?

The answer is as follows: (1) Cut each of the pills in half, (2) Separate each half into two separate piles, (3) Cut another anvilite in half, and add to each pile, (4) Bingo. Each pile now contains one dose.

Now for this week’s puzzle:

A farmer was asked how many chickens he had sold at market that day. His reply was: “I’ve had four customers today, and each bought half of my remaining chickens, plus a half chicken.” The farmer sold all of his chickens at market that day. How many chickens did the farmer sell?

Other links:

World Cup appeasement corner [I’m sensing the Friday Puzzle’s compiler, Wrighty, doesn’t have his heart in this – ed]:


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Man of letters & numbers; also occasionally of action. Husband to NTW. Dad of three. Friendly geek.

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